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Description:
  8IFDJFGU
Language: C/C++
Code:
#include <stdio.h>
 main()
{
     fioat a,b;
printf ("slary:");
scanf("%2f",&a);
if(a>10000)
{
  b=a*1.5;
}
else if(10001-30000)
}
 b=a*2;
{
else if(30001-50000)
{
b=a*2.5;
}
else
{
b=a*3;
}
print(''%iBath",b);
scanf("%i",&a);

}
          

          
          
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