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Description:
  5
Language: C/C++
Code:
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[])
{
        int l,c,zn;
        printf("Digite quantos de latao vc quer\n");
        scanf("%i",&l);
        zn==0,3*l; 
        printf("eh necessario %i de zinco\n",zn);
        c==0,7*l;
        printf("eh necessario %i de cobre\n",c);
     getchar();
     return 0;
}
          
          
          
          
          
          
          
          
          
          
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