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Description:
  2
Language: C/C++
Code:
#include <stdio.h>
int main(void)
{
    int i,b;
    printf("测试输出");
    if(i=1;i<10;i++)
    {
        if(b=1;b<=i;b++)
        {
            printf("%d*%d=%dt"i,b,a*b);
         }
        printf("n");
    }
    return 0;
}
          
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