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Description:
  1
Language: C/C++
Code:
#include <stdio.h>
#include<iostream1.h>
int main(void )
{
     doudle x,n,,y1,p,y;
     int i;
     do
     {
          cin>>x;
          printf("vvedite drygoe x");          
          x>=0;
     }while)x<0);
     y=1;
     i=0;
     while(i<n)
     {
          if y=(y*(y^2+3*x))\(3*(y^2)+x);
          i++;
          
     }
          y1=x^(1/2);
          p=(y1-y)/y;
          printf("y,y1.p");
     
     

     return 0;
}
          
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