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Description:
  n.c
Language: C/C++
Code:
#include <stdio.h>
int main()
{
int i,j,k;
int l=0;
int char a[10];
scanf("%d",&a[i]);
for(i=0;i<10;i++)
     {
          for(j=i+1;j<10;j++)
               {
                    for(k=j+1;k<10;k++);
                         {
                              if                                   {     
     a[i]+a[j]+a[k]=0
          printf("%d%d%d",a[i],a[j],a[k])
}
                         }
               }
     }
return 0;
}
          
          
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